My messy collection | Packet tracer project

HW Domnit Alexandru

Requirements

Implement given project in Packet Tracer.
Screenshots from each computer in the network to prove functionality.

Given initial data

Doc

Packet Tracer tutorial.
Understanding Address spaces and subnetting in IPv4.
ProiectComplet YT

Solution

Computations for network IP`s

Main Network IP:69.122.240.0/24
Subnet Mask:255.255.255.0
Total available IP`s: 2^8=256 (from /24 submask)
Given Sub-Network requirements:

N1: 56 IP’s
N2: 24 IP’s
N3: 12 IP’s
N4: 20 IP’s
N5: 4 IP’s

Identify all the present networks

Therefore we can find nontrivial networks as:
N5w: 2 ip`s
N12: 2 ip`s
N23: 2 ip`s
N34: 2 ip`s
N45: 2 ip`s

Computations for each subnet

For each subnet we add:
1 for Network Address (NA)
1 for Broadcast Address (BA)

Formula: Total required IP`s = Hosts + 1(NA) + 1(BA)

N1: 56 hosts

N1: 59 ip < 64 = 2^6 => 32-6 = 26 <=> /26

N2: 24 hosts

N2: 27 ip < 32 = 2^5 => 32-5 = 27 <=> /27

N3: 12 hosts

N3: 15 ip < 16 = 2^4 => 32-4 = 28 <=> /28

N4: 20 hosts

N4: 23 ip < 32 = 2^5 => 32-5 = 27 <=> /27

N5: 4 hosts

N5: 7 ip < 8 = 2^3 => 32-3 = 29 <=> /29

The other networks

N5w: 4 ip /30
N12: 4 ip /30
N23: 4 ip /30
N34: 4 ip /30
N45: 4 ip /30

Boildown of the computations:

Subnet	Hosts	Required IP`s	Allocated IP`s	Subnet Mask
N1	56	59	64	/26
N2	24	27	32	/27
N3	12	15	16	/28
N4	20	23	32	/27
N5	4	7	8	/29

Total allotted IP`s : 64+32+16+32+8+5*4=172
Since 172<256 this allocation fits.

Binary Tree

/24 256
/25 128
/26 64
/27 32
/28 16
/29 8
/30 4
N1=64 + N2=32 + N4=32 + N3=16 + N5=8 + 4 + 4 + 4 + 4 + 4

Now we can recursively split the range into appropriate chunks:

[0..63][64..95][96..127][128..143][144..151][152..155][156..159][160..163][164..167][168..171]

IP plan

Subnet	Range	Subnet Mask	Usage
N1	69.122.240.0 - 69.122.240.63	/26	R1=.1 S1DHCP=.2
N2	69.122.240.64 - 69.122.240.95	/27	R2=.65 S2WEB=.66
N3	69.122.240.128 - 69.122.240.144	/28	R3=.129 S3DNS=.130
N4	69.122.240.96 - 69.122.240.127	/27	R4=.97
N5	69.122.240.144 - 69.122.240.151	/29	R5=.145
N5W	69.122.240.152 - 69.122.240.155	/30	R5=.153 RW=.154
N12	69.122.240.156 - 69.122.240.159	/30	R1=.157 R2=.158
N23	69.122.240.160 - 69.122.240.163	/30	R2=.161 R3=.162
N34	69.122.240.164 - 69.122.240.167	/30	R3=.165 R4=.166
N45	69.122.240.168 - 69.122.240.171	/30	R4=.169 R5=.170

Implementation

I`ve implemented the reuqired network plan into PacketTracer by firstly creating each subnet and then linking them all together. All the router and server settings are done according to the enumeration above.